3x(2x+4)=6((x^2)+1)

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Solution for 3x(2x+4)=6((x^2)+1) equation: 


Simplifying
3x(2x + 4) = 6((x2) + 1)

Reorder the terms:
3x(4 + 2x) = 6((x2) + 1)
(4 * 3x + 2x * 3x) = 6((x2) + 1)
(12x + 6x2) = 6((x2) + 1)
12x + 6x2 = 6(x2 + 1)

Reorder the terms:
12x + 6x2 = 6(1 + x2)
12x + 6x2 = (1 * 6 + x2 * 6)
12x + 6x2 = (6 + 6x2)

Add '-6x2' to each side of the equation.
12x + 6x2 + -6x2 = 6 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
12x + 0 = 6 + 6x2 + -6x2
12x = 6 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
12x = 6 + 0
12x = 6

Solving
12x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '12'.
x = 0.5

Simplifying
x = 0.5

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